10m^2-33m-54=0

Solution for 10m^2-33m-54=0 equation:

10m^2-33m-54=0

a = 10; b = -33; c = -54;
Δ = b2-4ac
Δ = -332-4·10·(-54)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-57}{2*10}=\frac{-24}{20}
=-1+1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+57}{2*10}=\frac{90}{20}
=4+1/2
$